Part (a):
Sherlock
Holmes: “However innocent he might be, he could not be such an absolute
imbecile as not to see that the circumstances were very black against him. Had
he appeared surprised at his own arrest, or feigned indignation at it, I should
have looked upon it as highly suspicious because such surprise or anger would
not be natural under the circumstances, and yet might appear to be the best
policy to a scheming man.”
Let: C = He schemes to appear innocent
D = He feigns indignation
I
= He’s an imbecile
N = He’s innocent
R = He feigns surprise
S = He sees the evidence is against
him
T = He’s too innocent to see the
evidence
Represent
the following argument and prove its validity:
(1) He
sees how bad the evidence is against him unless he’s an imbecile or too
innocent to see it.
(2) But
he’s neither an imbecile nor too innocent to see the evidence against him.
(3) If
he sees the evidence against him, then he schemes to appear innocent—unless
he’s actually innocent.
(4) If
he schemes to appear innocent, then he feigns surprise or he feigns
indignation.
(5) But
he feigned neither surprise nor indignation.
:. He’s innocent
Part (b)
Holmes: “His
frank acceptance of the situation marks him as either an innocent man, or else
as a man of considerable self-restraint and firmness.”
Let: A = He accepts the situation
F = He has firmness
N = He’s innocent
S = He has self-restraint
Represent
Holmes’ claim as “He accepts the situation, and if he accepts the situation,
then he’s either an innocent man or else he has self-restraint and firmness.”
Show (by a line of a truth table) that the inference from Holmes’ claim to the
conclusion that “He’s innocent” would be an invalid inference. Prove that the
inference becomes valid if we add the following premise: “If he has
self-restraint, then he didn’t commit the crime; and if he didn’t commit the
crime, then he’s innocent” (where: R = He committed the crime)
Solution:
Part
(a):
(1) S v (I v T) Premise
(2) ~(I v T) Premise
(3) S → (C v N) Premise
(4) C → (R v D) Premise
(5) ~(R
v D) Premise
:. N
(6) S 1,
2 Disjunctive Syllogism
(7) C v N 3,
6 Modus Ponens
(8) ~C 4,
5 Disjunctive Syllogism
(9) N 7,
8 Disjunctive Syllogism
Part (b):
Holmes’
Claim: A & {A → [N v (S & F)]}
Yet this
doesn’t entail N: Let A = S = F = True,
but N = False. Then Holmes’ Claim is true but “He’s innocent” is false.
Added
Premise: [(S → ~R) & (~R → N)]
(1) A & {A → [N v (S & F)]} Premise
(2) [(S → ~R) & (~R → N)] Premise
(3) A 1,
&-Elimination
(4) A → [N v (S & F)] 1, &-Elimination
(5) N v (S & F) 3, 4 Modus Ponens
(6) ~N Assumption for
RAA
(7) (S & F) 5, 6 Disjunctive
Syllogism
(8) S 7, &-Elimination
(9) S → ~R 2,
&-Elimination
(10) ~R 8, 9 Modus Ponens
(11) ~R → N 2,
& Elimination
(12) N 10, 11 Modus Ponens
(13) N & ~N 6, 12
&-Introduction
(14) ~~N 6-13
RAA
(15) N 14,
DNE
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